Base | Representation |
---|---|
bin | 10101100000010101… |
… | …00110110100010111 |
3 | 1002210121220102111001 |
4 | 22300022212310113 |
5 | 142121122130142 |
6 | 5145352124131 |
7 | 556052113366 |
oct | 126012466427 |
9 | 32717812431 |
10 | 11545505047 |
11 | 499515590a |
12 | 22a2696647 |
13 | 111cc52bbb |
14 | 7b750d7dd |
15 | 4788e55b7 |
hex | 2b02a6d17 |
11545505047 has 2 divisors, whose sum is σ = 11545505048. Its totient is φ = 11545505046.
The previous prime is 11545505011. The next prime is 11545505051. The reversal of 11545505047 is 74050554511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11545505047 - 211 = 11545502999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11545504997 and 11545505015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11545505077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772752523 + 5772752524.
It is an arithmetic number, because the mean of its divisors is an integer number (5772752524).
Almost surely, 211545505047 is an apocalyptic number.
11545505047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11545505047 is an equidigital number, since it uses as much as digits as its factorization.
11545505047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70000, while the sum is 37.
The spelling of 11545505047 in words is "eleven billion, five hundred forty-five million, five hundred five thousand, forty-seven".
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