Base | Representation |
---|---|
bin | 10101100000010101… |
… | …00110110100011011 |
3 | 1002210121220102111012 |
4 | 22300022212310123 |
5 | 142121122130201 |
6 | 5145352124135 |
7 | 556052113403 |
oct | 126012466433 |
9 | 32717812435 |
10 | 11545505051 |
11 | 4995155913 |
12 | 22a269664b |
13 | 111cc52bc2 |
14 | 7b750d803 |
15 | 4788e55bb |
hex | 2b02a6d1b |
11545505051 has 2 divisors, whose sum is σ = 11545505052. Its totient is φ = 11545505050.
The previous prime is 11545505047. The next prime is 11545505077. The reversal of 11545505051 is 15050554511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11545505051 - 22 = 11545505047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11545504999 and 11545505017.
It is not a weakly prime, because it can be changed into another prime (11545505011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5772752525 + 5772752526.
It is an arithmetic number, because the mean of its divisors is an integer number (5772752526).
Almost surely, 211545505051 is an apocalyptic number.
11545505051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11545505051 is an equidigital number, since it uses as much as digits as its factorization.
11545505051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12500, while the sum is 32.
The spelling of 11545505051 in words is "eleven billion, five hundred forty-five million, five hundred five thousand, fifty-one".
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