115477735413149 has 2 divisors, whose sum is σ = 115477735413150. Its totient is φ = 115477735413148.

The previous prime is 115477735412983. The next prime is 115477735413151. The reversal of 115477735413149 is 941314537774511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108115700536900 + 7362034876249 = 10397870^2 + 2713307^2 .

It is a cyclic number.

It is not a de Polignac number, because 115477735413149 - 2²⁸ = 115477466977693 is a prime.

It is a super-2 number, since 2×115477735413149² (a number of 29 digits) contains 22 as substring.

Together with 115477735413151, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 115477735413091 and 115477735413100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115477735413199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57738867706574 + 57738867706575.

It is an arithmetic number, because the mean of its divisors is an integer number (57738867706575).

Almost surely, 2^{115477735413149} is an apocalyptic number.

It is an amenable number.

115477735413149 is a deficient number, since it is larger than the sum of its proper divisors (1).

115477735413149 is an equidigital number, since it uses as much as digits as its factorization.

115477735413149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 44452800, while the sum is 62.

The spelling of 115477735413149 in words is "one hundred fifteen trillion, four hundred seventy-seven billion, seven hundred thirty-five million, four hundred thirteen thousand, one hundred forty-nine".