Base | Representation |
---|---|
bin | 10101100000110101… |
… | …01010111110101101 |
3 | 1002210220211101100222 |
4 | 22300122222332231 |
5 | 142123211411042 |
6 | 5150022301125 |
7 | 556132653362 |
oct | 126032527655 |
9 | 32726741328 |
10 | 11549716397 |
11 | 499757196a |
12 | 22a3b877a5 |
13 | 1120a98a1b |
14 | 7b7cc8469 |
15 | 478e782d2 |
hex | 2b06aafad |
11549716397 has 2 divisors, whose sum is σ = 11549716398. Its totient is φ = 11549716396.
The previous prime is 11549716369. The next prime is 11549716417. The reversal of 11549716397 is 79361794511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7439752516 + 4109963881 = 86254^2 + 64109^2 .
It is a cyclic number.
It is not a de Polignac number, because 11549716397 - 220 = 11548667821 is a prime.
It is a super-2 number, since 2×115497163972 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11549716337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5774858198 + 5774858199.
It is an arithmetic number, because the mean of its divisors is an integer number (5774858199).
Almost surely, 211549716397 is an apocalyptic number.
It is an amenable number.
11549716397 is a deficient number, since it is larger than the sum of its proper divisors (1).
11549716397 is an equidigital number, since it uses as much as digits as its factorization.
11549716397 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1428840, while the sum is 53.
The spelling of 11549716397 in words is "eleven billion, five hundred forty-nine million, seven hundred sixteen thousand, three hundred ninety-seven".
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