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11555244120000 = 26354713756243
BaseRepresentation
bin1010100000100110101000…
…1110001001011111000000
31111220200002211102110102110
42220021222032021133000
53003310114443320000
640324223400015320
72301560502265230
oct250115216113700
944820084373373
1011555244120000
113755608074429
121367597a61540
1365a868904619
142bd3c3775cc0
151508a225a850
hexa826a3897c0

11555244120000 has 280 divisors, whose sum is σ = 43662098356096. Its totient is φ = 2641198464000.

The previous prime is 11555244119953. The next prime is 11555244120037. The reversal of 11555244120000 is 2144255511.

It is a tau number, because it is divible by the number of its divisors (280).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a self number, because there is not a number n which added to its sum of digits gives 11555244120000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 6038122 + ... + 7718121.

Almost surely, 211555244120000 is an apocalyptic number.

11555244120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11555244120000 is an abundant number, since it is smaller than the sum of its proper divisors (32106854236096).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11555244120000 is an equidigital number, since it uses as much as digits as its factorization.

11555244120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13756285 (or 13756260 counting only the distinct ones).

The product of its (nonzero) digits is 8000, while the sum is 30.

Adding to 11555244120000 its reverse (2144255511), we get a palindrome (11557388375511).

The spelling of 11555244120000 in words is "eleven trillion, five hundred fifty-five billion, two hundred forty-four million, one hundred twenty thousand".