Base | Representation |
---|---|
bin | 110101110011110100… |
… | …0011111011111011101 |
3 | 102001021020200112011121 |
4 | 1223213220133133131 |
5 | 3343124124120331 |
6 | 125030235050541 |
7 | 11230365566164 |
oct | 1534750373735 |
9 | 361236615147 |
10 | 115555301341 |
11 | 45008a56247 |
12 | 1a48b2a0a51 |
13 | ab87403c6c |
14 | 5842d143db |
15 | 3014b8cc11 |
hex | 1ae7a1f7dd |
115555301341 has 2 divisors, whose sum is σ = 115555301342. Its totient is φ = 115555301340.
The previous prime is 115555301333. The next prime is 115555301483. The reversal of 115555301341 is 143103555511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 61431605316 + 54123696025 = 247854^2 + 232645^2 .
It is a cyclic number.
It is not a de Polignac number, because 115555301341 - 23 = 115555301333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 115555301297 and 115555301306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115555401341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57777650670 + 57777650671.
It is an arithmetic number, because the mean of its divisors is an integer number (57777650671).
Almost surely, 2115555301341 is an apocalyptic number.
It is an amenable number.
115555301341 is a deficient number, since it is larger than the sum of its proper divisors (1).
115555301341 is an equidigital number, since it uses as much as digits as its factorization.
115555301341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22500, while the sum is 34.
Adding to 115555301341 its reverse (143103555511), we get a palindrome (258658856852).
The spelling of 115555301341 in words is "one hundred fifteen billion, five hundred fifty-five million, three hundred one thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •