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115555301341 is a prime number
BaseRepresentation
bin110101110011110100…
…0011111011111011101
3102001021020200112011121
41223213220133133131
53343124124120331
6125030235050541
711230365566164
oct1534750373735
9361236615147
10115555301341
1145008a56247
121a48b2a0a51
13ab87403c6c
145842d143db
153014b8cc11
hex1ae7a1f7dd

115555301341 has 2 divisors, whose sum is σ = 115555301342. Its totient is φ = 115555301340.

The previous prime is 115555301333. The next prime is 115555301483. The reversal of 115555301341 is 143103555511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 61431605316 + 54123696025 = 247854^2 + 232645^2 .

It is a cyclic number.

It is not a de Polignac number, because 115555301341 - 23 = 115555301333 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115555301297 and 115555301306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115555401341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57777650670 + 57777650671.

It is an arithmetic number, because the mean of its divisors is an integer number (57777650671).

Almost surely, 2115555301341 is an apocalyptic number.

It is an amenable number.

115555301341 is a deficient number, since it is larger than the sum of its proper divisors (1).

115555301341 is an equidigital number, since it uses as much as digits as its factorization.

115555301341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 22500, while the sum is 34.

Adding to 115555301341 its reverse (143103555511), we get a palindrome (258658856852).

The spelling of 115555301341 in words is "one hundred fifteen billion, five hundred fifty-five million, three hundred one thousand, three hundred forty-one".