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115704573146117 is a prime number
BaseRepresentation
bin11010010011101110010001…
…111110110011010000000101
3120011200020201122100012101022
4122103232101332303100011
5110131200431211133432
61050025540324040525
733241244120305034
oct3223562176632005
9504606648305338
10115704573146117
113395a04114674a
1210b883a3533145
134c73b820a9977
1420801ba0d871b
15d59b1c727b12
hex693b91fb3405

115704573146117 has 2 divisors, whose sum is σ = 115704573146118. Its totient is φ = 115704573146116.

The previous prime is 115704573146069. The next prime is 115704573146137. The reversal of 115704573146117 is 711641375407511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68832393447841 + 46872179698276 = 8296529^2 + 6846326^2 .

It is a cyclic number.

It is not a de Polignac number, because 115704573146117 - 222 = 115704568951813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (115704573146137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57852286573058 + 57852286573059.

It is an arithmetic number, because the mean of its divisors is an integer number (57852286573059).

Almost surely, 2115704573146117 is an apocalyptic number.

It is an amenable number.

115704573146117 is a deficient number, since it is larger than the sum of its proper divisors (1).

115704573146117 is an equidigital number, since it uses as much as digits as its factorization.

115704573146117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2469600, while the sum is 53.

The spelling of 115704573146117 in words is "one hundred fifteen trillion, seven hundred four billion, five hundred seventy-three million, one hundred forty-six thousand, one hundred seventeen".