Base | Representation |
---|---|
bin | 11010010111100010101011… |
… | …110001011110000010101111 |
3 | 120012121100002112121221001202 |
4 | 122113202223301132002233 |
5 | 110200000403202122142 |
6 | 1050350300454000115 |
7 | 33266224224145502 |
oct | 3227425361360257 |
9 | 505540075557052 |
10 | 115966998864047 |
11 | 33a50367672771 |
12 | 1100b22134603b |
13 | 4c92844577876 |
14 | 208cb92ca5139 |
15 | d6187b356032 |
hex | 6978abc5e0af |
115966998864047 has 2 divisors, whose sum is σ = 115966998864048. Its totient is φ = 115966998864046.
The previous prime is 115966998863977. The next prime is 115966998864049. The reversal of 115966998864047 is 740468899669511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-115966998864047 is a prime.
Together with 115966998864049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (115966998864049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57983499432023 + 57983499432024.
It is an arithmetic number, because the mean of its divisors is an integer number (57983499432024).
Almost surely, 2115966998864047 is an apocalyptic number.
115966998864047 is a deficient number, since it is larger than the sum of its proper divisors (1).
115966998864047 is an equidigital number, since it uses as much as digits as its factorization.
115966998864047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5643509760, while the sum is 83.
The spelling of 115966998864047 in words is "one hundred fifteen trillion, nine hundred sixty-six billion, nine hundred ninety-eight million, eight hundred sixty-four thousand, forty-seven".
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