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11609542502653 is a prime number
BaseRepresentation
bin1010100011110000111010…
…1010000010100011111101
31112002212020222102002112211
42220330032222002203331
53010202320340041103
640405203350500421
72305522200026644
oct250741652024375
945085228362484
1011609542502653
11377664109aa37
121376010364711
13662a10048624
142c1c94ccc35b
15151ece16536d
hexa8f0ea828fd

11609542502653 has 2 divisors, whose sum is σ = 11609542502654. Its totient is φ = 11609542502652.

The previous prime is 11609542502533. The next prime is 11609542502681. The reversal of 11609542502653 is 35620524590611.

It is a happy number.

11609542502653 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11604467080089 + 5075422564 = 3406533^2 + 71242^2 .

It is a cyclic number.

It is not a de Polignac number, because 11609542502653 - 213 = 11609542494461 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11609542502597 and 11609542502606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11609542502053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5804771251326 + 5804771251327.

It is an arithmetic number, because the mean of its divisors is an integer number (5804771251327).

Almost surely, 211609542502653 is an apocalyptic number.

It is an amenable number.

11609542502653 is a deficient number, since it is larger than the sum of its proper divisors (1).

11609542502653 is an equidigital number, since it uses as much as digits as its factorization.

11609542502653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944000, while the sum is 49.

The spelling of 11609542502653 in words is "eleven trillion, six hundred nine billion, five hundred forty-two million, five hundred two thousand, six hundred fifty-three".