Search a number
-
+
1161032533 is a prime number
BaseRepresentation
bin100010100110011…
…1111001101010101
32222220200120012221
41011030333031111
54334211020113
6311112542341
740525420333
oct10514771525
92886616187
101161032533
11546410a21
122849b19b1
131566cc8cb
14b02a8b53
156bdde98d
hex4533f355

1161032533 has 2 divisors, whose sum is σ = 1161032534. Its totient is φ = 1161032532.

The previous prime is 1161032473. The next prime is 1161032539. The reversal of 1161032533 is 3352301611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1131515044 + 29517489 = 33638^2 + 5433^2 .

It is an emirp because it is prime and its reverse (3352301611) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1161032533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1161032498 and 1161032507.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1161032539) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580516266 + 580516267.

It is an arithmetic number, because the mean of its divisors is an integer number (580516267).

Almost surely, 21161032533 is an apocalyptic number.

It is an amenable number.

1161032533 is a deficient number, since it is larger than the sum of its proper divisors (1).

1161032533 is an equidigital number, since it uses as much as digits as its factorization.

1161032533 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

The square root of 1161032533 is about 34073.9274666129. The cubic root of 1161032533 is about 1051.0292350828.

The spelling of 1161032533 in words is "one billion, one hundred sixty-one million, thirty-two thousand, five hundred thirty-three".