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116123643244303 is a prime number
BaseRepresentation
bin11010011001110100100100…
…100000010110111100001111
3120020011022102100122221010221
4122121310210200112330033
5110210032210132304203
61050550244254412211
733313441063334662
oct3231644440267417
9506138370587127
10116123643244303
1134000840302072
1211035659201067
134ca4549559b76
1420965b2c816d9
15d65998405abd
hex699d24816f0f

116123643244303 has 2 divisors, whose sum is σ = 116123643244304. Its totient is φ = 116123643244302.

The previous prime is 116123643244291. The next prime is 116123643244339. The reversal of 116123643244303 is 303442346321611.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 116123643244303 - 29 = 116123643243791 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 116123643244303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116123643244373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58061821622151 + 58061821622152.

It is an arithmetic number, because the mean of its divisors is an integer number (58061821622152).

Almost surely, 2116123643244303 is an apocalyptic number.

116123643244303 is a deficient number, since it is larger than the sum of its proper divisors (1).

116123643244303 is an equidigital number, since it uses as much as digits as its factorization.

116123643244303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 746496, while the sum is 43.

Adding to 116123643244303 its reverse (303442346321611), we get a palindrome (419565989565914).

The spelling of 116123643244303 in words is "one hundred sixteen trillion, one hundred twenty-three billion, six hundred forty-three million, two hundred forty-four thousand, three hundred three".