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116125260997 is a prime number
BaseRepresentation
bin110110000100110011…
…0101101110011000101
3102002201222011110211111
41230021212231303011
53400311031322442
6125202555205021
711250456301144
oct1541146556305
9362658143744
10116125260997
1145280756389
121a60a146771
13ac485123b5
1458988bb75b
153049c24b17
hex1b099adcc5

116125260997 has 2 divisors, whose sum is σ = 116125260998. Its totient is φ = 116125260996.

The previous prime is 116125260919. The next prime is 116125261009. The reversal of 116125260997 is 799062521611.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 59535512001 + 56589748996 = 243999^2 + 237886^2 .

It is an emirp because it is prime and its reverse (799062521611) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-116125260997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 116125260997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (116125263997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58062630498 + 58062630499.

It is an arithmetic number, because the mean of its divisors is an integer number (58062630499).

Almost surely, 2116125260997 is an apocalyptic number.

It is an amenable number.

116125260997 is a deficient number, since it is larger than the sum of its proper divisors (1).

116125260997 is an equidigital number, since it uses as much as digits as its factorization.

116125260997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 408240, while the sum is 49.

The spelling of 116125260997 in words is "one hundred sixteen billion, one hundred twenty-five million, two hundred sixty thousand, nine hundred ninety-seven".