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11613400413127 is a prime number
BaseRepresentation
bin1010100011111111010010…
…0110110011001111000111
31112010020012211202020210221
42220333310212303033013
53010233221001210002
640411042243125211
72306016613521232
oct250776446631707
945106184666727
1011613400413127
1137782408551a7
121376908373807
136631a63aa8a6
142c213d416419
15152157bbec37
hexa8ff49b33c7

11613400413127 has 2 divisors, whose sum is σ = 11613400413128. Its totient is φ = 11613400413126.

The previous prime is 11613400413103. The next prime is 11613400413157. The reversal of 11613400413127 is 72131400431611.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11613400413127 - 223 = 11613392024519 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11613400413092 and 11613400413101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11613400413157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806700206563 + 5806700206564.

It is an arithmetic number, because the mean of its divisors is an integer number (5806700206564).

Almost surely, 211613400413127 is an apocalyptic number.

11613400413127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11613400413127 is an equidigital number, since it uses as much as digits as its factorization.

11613400413127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 34.

Adding to 11613400413127 its reverse (72131400431611), we get a palindrome (83744800844738).

The spelling of 11613400413127 in words is "eleven trillion, six hundred thirteen billion, four hundred million, four hundred thirteen thousand, one hundred twenty-seven".