1161425117 has 2 divisors, whose sum is σ = 1161425118. Its totient is φ = 1161425116.

The previous prime is 1161425113. The next prime is 1161425119. The reversal of 1161425117 is 7115241611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1144401241 + 17023876 = 33829^2 + 4126^2 .

It is a cyclic number.

It is not a de Polignac number, because 1161425117 - 2² = 1161425113 is a prime.

Together with 1161425119, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1161425117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1161425113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580712558 + 580712559.

It is an arithmetic number, because the mean of its divisors is an integer number (580712559).

Almost surely, 2^1161425117 is an apocalyptic number.

It is an amenable number.

1161425117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1161425117 is an equidigital number, since it uses as much as digits as its factorization.

1161425117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1680, while the sum is 29.

The square root of 1161425117 is about 34079.6877479827. The cubic root of 1161425117 is about 1051.1476844663.

Adding to 1161425117 its reverse (7115241611), we get a palindrome (8276666728).

The spelling of 1161425117 in words is "one billion, one hundred sixty-one million, four hundred twenty-five thousand, one hundred seventeen".