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1161728143 is a prime number
BaseRepresentation
bin100010100111110…
…1001000010001111
32222221222220102021
41011033221002033
54334400300033
6311135511011
740534345342
oct10517510217
92887886367
101161728143
11546846604
12285088467
131568b4404
14b040a459
156becab2d
hex453e908f

1161728143 has 2 divisors, whose sum is σ = 1161728144. Its totient is φ = 1161728142.

The previous prime is 1161728123. The next prime is 1161728171. The reversal of 1161728143 is 3418271611.

It is a weak prime.

It is an emirp because it is prime and its reverse (3418271611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1161728143 - 25 = 1161728111 is a prime.

It is a super-2 number, since 2×11617281432 = 2699224556476456898, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1161728099 and 1161728108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1161728123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580864071 + 580864072.

It is an arithmetic number, because the mean of its divisors is an integer number (580864072).

Almost surely, 21161728143 is an apocalyptic number.

1161728143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1161728143 is an equidigital number, since it uses as much as digits as its factorization.

1161728143 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8064, while the sum is 34.

The square root of 1161728143 is about 34084.1333027554. The cubic root of 1161728143 is about 1051.2390944005.

Adding to 1161728143 its reverse (3418271611), we get a palindrome (4579999754).

The spelling of 1161728143 in words is "one billion, one hundred sixty-one million, seven hundred twenty-eight thousand, one hundred forty-three".