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116221004147 is a prime number
BaseRepresentation
bin110110000111101001…
…1111100100101110011
3102002222122022201202002
41230033103330211303
53401010034113042
6125220255244215
711253031143533
oct1541723744563
9362878281662
10116221004147
114531a7aa656
121a63621966b
13ac622c5451
1458a74c14c3
153053338132
hex1b0f4fc973

116221004147 has 2 divisors, whose sum is σ = 116221004148. Its totient is φ = 116221004146.

The previous prime is 116221003981. The next prime is 116221004149. The reversal of 116221004147 is 741400122611.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (741400122611) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 116221004147 - 28 = 116221003891 is a prime.

Together with 116221004149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (116221004149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58110502073 + 58110502074.

It is an arithmetic number, because the mean of its divisors is an integer number (58110502074).

Almost surely, 2116221004147 is an apocalyptic number.

116221004147 is a deficient number, since it is larger than the sum of its proper divisors (1).

116221004147 is an equidigital number, since it uses as much as digits as its factorization.

116221004147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 116221004147 its reverse (741400122611), we get a palindrome (857621126758).

The spelling of 116221004147 in words is "one hundred sixteen billion, two hundred twenty-one million, four thousand, one hundred forty-seven".