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11625204252133 is a prime number
BaseRepresentation
bin1010100100101011010000…
…1010110111110111100101
31112011100200110202101212101
42221022310022313313211
53010431404242032013
640420313424252101
72306615253510103
oct251126412676745
945140613671771
1011625204252133
11378224880614a
121379061471031
13664337a00604
142c293cd70c73
151525e90e38dd
hexa92b42b7de5

11625204252133 has 2 divisors, whose sum is σ = 11625204252134. Its totient is φ = 11625204252132.

The previous prime is 11625204252127. The next prime is 11625204252157. The reversal of 11625204252133 is 33125240252611.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7488853676929 + 4136350575204 = 2736577^2 + 2033802^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11625204252133 is a prime.

It is a super-2 number, since 2×116252042521332 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11625204252092 and 11625204252101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11625204250133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5812602126066 + 5812602126067.

It is an arithmetic number, because the mean of its divisors is an integer number (5812602126067).

Almost surely, 211625204252133 is an apocalyptic number.

It is an amenable number.

11625204252133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11625204252133 is an equidigital number, since it uses as much as digits as its factorization.

11625204252133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 37.

The spelling of 11625204252133 in words is "eleven trillion, six hundred twenty-five billion, two hundred four million, two hundred fifty-two thousand, one hundred thirty-three".