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11627796473 is a prime number
BaseRepresentation
bin10101101010001001…
…00001011111111001
31010000100202021002122
422311010201133321
5142303203441343
65201452011025
7561101432156
oct126504413771
933010667078
1011627796473
114a27651657
122306160a75
131134006257
147c441122d
15480c4d068
hex2b51217f9

11627796473 has 2 divisors, whose sum is σ = 11627796474. Its totient is φ = 11627796472.

The previous prime is 11627796437. The next prime is 11627796517. The reversal of 11627796473 is 37469772611.

It is a happy number.

Together with previous prime (11627796437) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10034429584 + 1593366889 = 100172^2 + 39917^2 .

It is a cyclic number.

It is not a de Polignac number, because 11627796473 - 214 = 11627780089 is a prime.

It is a super-2 number, since 2×116277964732 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11627796673) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5813898236 + 5813898237.

It is an arithmetic number, because the mean of its divisors is an integer number (5813898237).

Almost surely, 211627796473 is an apocalyptic number.

It is an amenable number.

11627796473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11627796473 is an equidigital number, since it uses as much as digits as its factorization.

11627796473 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2667168, while the sum is 53.

The spelling of 11627796473 in words is "eleven billion, six hundred twenty-seven million, seven hundred ninety-six thousand, four hundred seventy-three".