Base | Representation |
---|---|
bin | 100010101010110… |
… | …1100001110000011 |
3 | 10000001222110212121 |
4 | 1011111230032003 |
5 | 4340302022201 |
6 | 311233505111 |
7 | 40554002104 |
oct | 10525541603 |
9 | 3001873777 |
10 | 1163314051 |
11 | 54772a079 |
12 | 285712197 |
13 | 15701b213 |
14 | b07003ab |
15 | 6c1e09a1 |
hex | 4556c383 |
1163314051 has 2 divisors, whose sum is σ = 1163314052. Its totient is φ = 1163314050.
The previous prime is 1163314049. The next prime is 1163314111. The reversal of 1163314051 is 1504133611.
It is a weak prime.
It is an emirp because it is prime and its reverse (1504133611) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1163314051 - 21 = 1163314049 is a prime.
Together with 1163314049, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1163314021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 581657025 + 581657026.
It is an arithmetic number, because the mean of its divisors is an integer number (581657026).
Almost surely, 21163314051 is an apocalyptic number.
1163314051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1163314051 is an equidigital number, since it uses as much as digits as its factorization.
1163314051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
The square root of 1163314051 is about 34107.3899763673. The cubic root of 1163314051 is about 1051.7172356482.
Adding to 1163314051 its reverse (1504133611), we get a palindrome (2667447662).
The spelling of 1163314051 in words is "one billion, one hundred sixty-three million, three hundred fourteen thousand, fifty-one".
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