Base | Representation |
---|---|
bin | 110110001100110110… |
… | …0011100111010010111 |
3 | 102010102210002210201221 |
4 | 1230121230130322113 |
5 | 3401334132401101 |
6 | 125245441031211 |
7 | 11260244606566 |
oct | 1543154347227 |
9 | 363383083657 |
10 | 116395200151 |
11 | 453aa06869a |
12 | 1a684625507 |
13 | ac8c4165c9 |
14 | 58c26a7bdd |
15 | 3063796aa1 |
hex | 1b19b1ce97 |
116395200151 has 2 divisors, whose sum is σ = 116395200152. Its totient is φ = 116395200150.
The previous prime is 116395200133. The next prime is 116395200167. The reversal of 116395200151 is 151002593611.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 116395200151 - 213 = 116395191959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (116395200121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58197600075 + 58197600076.
It is an arithmetic number, because the mean of its divisors is an integer number (58197600076).
Almost surely, 2116395200151 is an apocalyptic number.
116395200151 is a deficient number, since it is larger than the sum of its proper divisors (1).
116395200151 is an equidigital number, since it uses as much as digits as its factorization.
116395200151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 34.
Adding to 116395200151 its reverse (151002593611), we get a palindrome (267397793762).
The spelling of 116395200151 in words is "one hundred sixteen billion, three hundred ninety-five million, two hundred thousand, one hundred fifty-one".
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