Base | Representation |
---|---|
bin | 110110010111110101… |
… | …1010110111100001111 |
3 | 102011101111002101220021 |
4 | 1230233223112330033 |
5 | 3403113041343203 |
6 | 125350214003011 |
7 | 11302343504641 |
oct | 1545753267417 |
9 | 364344071807 |
10 | 116764012303 |
11 | 45579271724 |
12 | 1a768046467 |
13 | b01a958353 |
14 | 5919670891 |
15 | 3085d495bd |
hex | 1b2fad6f0f |
116764012303 has 2 divisors, whose sum is σ = 116764012304. Its totient is φ = 116764012302.
The previous prime is 116764012283. The next prime is 116764012319. The reversal of 116764012303 is 303210467611.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-116764012303 is a prime.
It is a super-3 number, since 3×1167640123033 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (116764012003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58382006151 + 58382006152.
It is an arithmetic number, because the mean of its divisors is an integer number (58382006152).
Almost surely, 2116764012303 is an apocalyptic number.
116764012303 is a deficient number, since it is larger than the sum of its proper divisors (1).
116764012303 is an equidigital number, since it uses as much as digits as its factorization.
116764012303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18144, while the sum is 34.
Adding to 116764012303 its reverse (303210467611), we get a palindrome (419974479914).
The spelling of 116764012303 in words is "one hundred sixteen billion, seven hundred sixty-four million, twelve thousand, three hundred three".
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