Base | Representation |
---|---|
bin | 11010100111001001000011… |
… | …011011111110101010000001 |
3 | 120100101211002110111100201202 |
4 | 122213021003123332222001 |
5 | 110320031322444132001 |
6 | 1052530545253110545 |
7 | 33436534166312366 |
oct | 3247110333765201 |
9 | 510354073440652 |
10 | 117038990224001 |
11 | 34323a5886595a |
12 | 11162b35028455 |
13 | 503c9636cb541 |
14 | 20c8a085b046d |
15 | d7e6bce3596b |
hex | 6a72436fea81 |
117038990224001 has 2 divisors, whose sum is σ = 117038990224002. Its totient is φ = 117038990224000.
The previous prime is 117038990223899. The next prime is 117038990224003. The reversal of 117038990224001 is 100422099830711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116875126374400 + 163863849601 = 10810880^2 + 404801^2 .
It is a cyclic number.
It is not a de Polignac number, because 117038990224001 - 210 = 117038990222977 is a prime.
Together with 117038990224003, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (117038990224003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58519495112000 + 58519495112001.
It is an arithmetic number, because the mean of its divisors is an integer number (58519495112001).
Almost surely, 2117038990224001 is an apocalyptic number.
It is an amenable number.
117038990224001 is a deficient number, since it is larger than the sum of its proper divisors (1).
117038990224001 is an equidigital number, since it uses as much as digits as its factorization.
117038990224001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 47.
The spelling of 117038990224001 in words is "one hundred seventeen trillion, thirty-eight billion, nine hundred ninety million, two hundred twenty-four thousand, one".
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