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1171057326041 is a prime number
BaseRepresentation
bin10001000010101000011…
…101001011011111011001
311010221200222221221021002
4101002220131023133121
5123141311133413131
62253550514354345
7150414615014261
oct21025035133731
94127628857232
101171057326041
11411708370839
1216ab6088b9b5
13865792b1925
14409726b07a1
15206ddd186cb
hex110a874b7d9

1171057326041 has 2 divisors, whose sum is σ = 1171057326042. Its totient is φ = 1171057326040.

The previous prime is 1171057326017. The next prime is 1171057326073. The reversal of 1171057326041 is 1406237501711.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 703719654400 + 467337671641 = 838880^2 + 683621^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1171057326041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1171057325986 and 1171057326004.

It is not a weakly prime, because it can be changed into another prime (1171057326841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585528663020 + 585528663021.

It is an arithmetic number, because the mean of its divisors is an integer number (585528663021).

Almost surely, 21171057326041 is an apocalyptic number.

It is an amenable number.

1171057326041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1171057326041 is an equidigital number, since it uses as much as digits as its factorization.

1171057326041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 35280, while the sum is 38.

The spelling of 1171057326041 in words is "one trillion, one hundred seventy-one billion, fifty-seven million, three hundred twenty-six thousand, forty-one".