Base | Representation |
---|---|
bin | 10001000011000001011… |
… | …010001111001011101101 |
3 | 11010222210011202000120101 |
4 | 101003001122033023231 |
5 | 123143140323011013 |
6 | 2254100231551101 |
7 | 150431160401566 |
oct | 21030132171355 |
9 | 4128704660511 |
10 | 1171475985133 |
11 | 411902720593 |
12 | 16b058b2b491 |
13 | 86614c571bc |
14 | 409b213116d |
15 | 207159658dd |
hex | 110c168f2ed |
1171475985133 has 2 divisors, whose sum is σ = 1171475985134. Its totient is φ = 1171475985132.
The previous prime is 1171475985091. The next prime is 1171475985149. The reversal of 1171475985133 is 3315895741711.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1043703337924 + 127772647209 = 1021618^2 + 357453^2 .
It is a cyclic number.
It is not a de Polignac number, because 1171475985133 - 217 = 1171475854061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1171475985193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585737992566 + 585737992567.
It is an arithmetic number, because the mean of its divisors is an integer number (585737992567).
Almost surely, 21171475985133 is an apocalyptic number.
It is an amenable number.
1171475985133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1171475985133 is an equidigital number, since it uses as much as digits as its factorization.
1171475985133 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3175200, while the sum is 55.
The spelling of 1171475985133 in words is "one trillion, one hundred seventy-one billion, four hundred seventy-five million, nine hundred eighty-five thousand, one hundred thirty-three".
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