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1171475985133 is a prime number
BaseRepresentation
bin10001000011000001011…
…010001111001011101101
311010222210011202000120101
4101003001122033023231
5123143140323011013
62254100231551101
7150431160401566
oct21030132171355
94128704660511
101171475985133
11411902720593
1216b058b2b491
1386614c571bc
14409b213116d
15207159658dd
hex110c168f2ed

1171475985133 has 2 divisors, whose sum is σ = 1171475985134. Its totient is φ = 1171475985132.

The previous prime is 1171475985091. The next prime is 1171475985149. The reversal of 1171475985133 is 3315895741711.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1043703337924 + 127772647209 = 1021618^2 + 357453^2 .

It is a cyclic number.

It is not a de Polignac number, because 1171475985133 - 217 = 1171475854061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1171475985193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585737992566 + 585737992567.

It is an arithmetic number, because the mean of its divisors is an integer number (585737992567).

Almost surely, 21171475985133 is an apocalyptic number.

It is an amenable number.

1171475985133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1171475985133 is an equidigital number, since it uses as much as digits as its factorization.

1171475985133 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3175200, while the sum is 55.

The spelling of 1171475985133 in words is "one trillion, one hundred seventy-one billion, four hundred seventy-five million, nine hundred eighty-five thousand, one hundred thirty-three".