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11723647043 is a prime number
BaseRepresentation
bin10101110101100100…
…01010100001000011
31010021001002222100202
422322302022201003
5143002223201133
65215154235415
7563344232663
oct127262124103
933231088322
1011723647043
114a767695a9
122332285b6b
13114ab26174
147d30421a3
154893832e8
hex2bac8a843

11723647043 has 2 divisors, whose sum is σ = 11723647044. Its totient is φ = 11723647042.

The previous prime is 11723647021. The next prime is 11723647063. The reversal of 11723647043 is 34074632711.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11723647043 - 222 = 11719452739 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11723646988 and 11723647006.

It is not a weakly prime, because it can be changed into another prime (11723647003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5861823521 + 5861823522.

It is an arithmetic number, because the mean of its divisors is an integer number (5861823522).

Almost surely, 211723647043 is an apocalyptic number.

11723647043 is a deficient number, since it is larger than the sum of its proper divisors (1).

11723647043 is an equidigital number, since it uses as much as digits as its factorization.

11723647043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 84672, while the sum is 38.

The spelling of 11723647043 in words is "eleven billion, seven hundred twenty-three million, six hundred forty-seven thousand, forty-three".