Base | Representation |
---|---|
bin | 1101111110011… |
… | …11010111010101 |
3 | 22011121110211102 |
4 | 12333033113111 |
5 | 220003210201 |
6 | 15344515445 |
7 | 2622351242 |
oct | 677172725 |
9 | 264543742 |
10 | 117241301 |
11 | 601a8141 |
12 | 3331bb85 |
13 | 1b39c368 |
14 | 117dc5c9 |
15 | a45d26b |
hex | 6fcf5d5 |
117241301 has 2 divisors, whose sum is σ = 117241302. Its totient is φ = 117241300.
The previous prime is 117241283. The next prime is 117241331. The reversal of 117241301 is 103142711.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 67256401 + 49984900 = 8201^2 + 7070^2 .
It is a cyclic number.
It is not a de Polignac number, because 117241301 - 226 = 50132437 is a prime.
It is a super-4 number, since 4×1172413014 (a number of 33 digits) contains 4444 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117241331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58620650 + 58620651.
It is an arithmetic number, because the mean of its divisors is an integer number (58620651).
Almost surely, 2117241301 is an apocalyptic number.
It is an amenable number.
117241301 is a deficient number, since it is larger than the sum of its proper divisors (1).
117241301 is an equidigital number, since it uses as much as digits as its factorization.
117241301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 20.
The square root of 117241301 is about 10827.8022239049. The cubic root of 117241301 is about 489.4333321486.
The spelling of 117241301 in words is "one hundred seventeen million, two hundred forty-one thousand, three hundred one".
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