Base | Representation |
---|---|
bin | 1010101010011011110011… |
… | …1110110110101111000101 |
3 | 1112111211001012221102021011 |
4 | 2222212330332312233011 |
5 | 3014042012401011032 |
6 | 40533554402322221 |
7 | 2320020012434242 |
oct | 252467476665705 |
9 | 45454035842234 |
10 | 11724136344517 |
11 | 38101a6356473 |
12 | 1394271659371 |
13 | 6707731b784c |
14 | 2c76462485c9 |
15 | 154e896d6247 |
hex | aa9bcfb6bc5 |
11724136344517 has 2 divisors, whose sum is σ = 11724136344518. Its totient is φ = 11724136344516.
The previous prime is 11724136344493. The next prime is 11724136344521. The reversal of 11724136344517 is 71544363142711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9350715715236 + 2373420629281 = 3057894^2 + 1540591^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11724136344517 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11724136344017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5862068172258 + 5862068172259.
It is an arithmetic number, because the mean of its divisors is an integer number (5862068172259).
Almost surely, 211724136344517 is an apocalyptic number.
It is an amenable number.
11724136344517 is a deficient number, since it is larger than the sum of its proper divisors (1).
11724136344517 is an equidigital number, since it uses as much as digits as its factorization.
11724136344517 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1693440, while the sum is 49.
The spelling of 11724136344517 in words is "eleven trillion, seven hundred twenty-four billion, one hundred thirty-six million, three hundred forty-four thousand, five hundred seventeen".
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