11724136344493 has 2 divisors, whose sum is σ = 11724136344494. Its totient is φ = 11724136344492.

The previous prime is 11724136344491. The next prime is 11724136344517. The reversal of 11724136344493 is 39444363142711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8016497520964 + 3707638823529 = 2831342^2 + 1925523^2 .

It is a cyclic number.

It is not a de Polignac number, because 11724136344493 - 2¹ = 11724136344491 is a prime.

It is a super-3 number, since 3×11724136344493³ (a number of 40 digits) contains 333 as substring.

Together with 11724136344491, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11724136344493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11724136344491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5862068172246 + 5862068172247.

It is an arithmetic number, because the mean of its divisors is an integer number (5862068172247).

Almost surely, 2^{11724136344493} is an apocalyptic number.

It is an amenable number.

11724136344493 is a deficient number, since it is larger than the sum of its proper divisors (1).

11724136344493 is an equidigital number, since it uses as much as digits as its factorization.

11724136344493 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5225472, while the sum is 52.

The spelling of 11724136344493 in words is "eleven trillion, seven hundred twenty-four billion, one hundred thirty-six million, three hundred forty-four thousand, four hundred ninety-three".