Base | Representation |
---|---|
bin | 11010101011001111000000… |
… | …100011100110000101011111 |
3 | 120101101201002210102120101211 |
4 | 122223033000203212011133 |
5 | 110334133344113344001 |
6 | 1053304103500445251 |
7 | 33466052316126214 |
oct | 3253170043460537 |
9 | 511351083376354 |
10 | 117320262246751 |
11 | 34422275561703 |
12 | 111a9552549827 |
13 | 506033a5430b5 |
14 | 20d848c347b0b |
15 | d86b8138e351 |
hex | 6ab3c08e615f |
117320262246751 has 2 divisors, whose sum is σ = 117320262246752. Its totient is φ = 117320262246750.
The previous prime is 117320262246731. The next prime is 117320262246763. The reversal of 117320262246751 is 157642262023711.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 117320262246751 - 213 = 117320262238559 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 117320262246695 and 117320262246704.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (117320262246731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58660131123375 + 58660131123376.
It is an arithmetic number, because the mean of its divisors is an integer number (58660131123376).
Almost surely, 2117320262246751 is an apocalyptic number.
117320262246751 is a deficient number, since it is larger than the sum of its proper divisors (1).
117320262246751 is an equidigital number, since it uses as much as digits as its factorization.
117320262246751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1693440, while the sum is 49.
The spelling of 117320262246751 in words is "one hundred seventeen trillion, three hundred twenty billion, two hundred sixty-two million, two hundred forty-six thousand, seven hundred fifty-one".
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