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1175278980131 is a prime number
BaseRepresentation
bin10001000110100100000…
…101100000110000100011
311011100121012202011221222
4101012210011200300203
5123223432404331011
62255525443205255
7150624336333554
oct21064405406043
94140535664858
101175278980131
11413484387a63
1216b93a67682b
1386a9cacc8b9
1440c5324232b
1520889773ddb
hex111a4160c23

1175278980131 has 2 divisors, whose sum is σ = 1175278980132. Its totient is φ = 1175278980130.

The previous prime is 1175278980121. The next prime is 1175278980133. The reversal of 1175278980131 is 1310898725711.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1175278980131 is a prime.

It is a super-2 number, since 2×11752789801312 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1175278980133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1175278980133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 587639490065 + 587639490066.

It is an arithmetic number, because the mean of its divisors is an integer number (587639490066).

Almost surely, 21175278980131 is an apocalyptic number.

1175278980131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1175278980131 is an equidigital number, since it uses as much as digits as its factorization.

1175278980131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 846720, while the sum is 53.

The spelling of 1175278980131 in words is "one trillion, one hundred seventy-five billion, two hundred seventy-eight million, nine hundred eighty thousand, one hundred thirty-one".