Base | Representation |
---|---|
bin | 10101111010001000… |
… | …10010010100101111 |
3 | 1010100201012001221121 |
4 | 22331010102110233 |
5 | 143042024431142 |
6 | 5223043241411 |
7 | 564320641246 |
oct | 127504222457 |
9 | 33321161847 |
10 | 11761952047 |
11 | 4a9635172a |
12 | 2343079267 |
13 | 1155a48351 |
14 | 7d817395d |
15 | 48c8ecc67 |
hex | 2bd11252f |
11761952047 has 2 divisors, whose sum is σ = 11761952048. Its totient is φ = 11761952046.
The previous prime is 11761952003. The next prime is 11761952057. The reversal of 11761952047 is 74025916711.
It is a happy number.
11761952047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11761952047 - 231 = 9614468399 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11761951994 and 11761952012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11761952057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5880976023 + 5880976024.
It is an arithmetic number, because the mean of its divisors is an integer number (5880976024).
Almost surely, 211761952047 is an apocalyptic number.
11761952047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11761952047 is an equidigital number, since it uses as much as digits as its factorization.
11761952047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 105840, while the sum is 43.
The spelling of 11761952047 in words is "eleven billion, seven hundred sixty-one million, nine hundred fifty-two thousand, forty-seven".
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