Base | Representation |
---|---|
bin | 10101111010101100… |
… | …01011100011001101 |
3 | 1010101001000101120122 |
4 | 22331112023203031 |
5 | 143044230033033 |
6 | 5223331554325 |
7 | 564405546215 |
oct | 127526134315 |
9 | 33331011518 |
10 | 11766642893 |
11 | 4a98a65a65 |
12 | 234475b9a5 |
13 | 11569cb4b5 |
14 | 7d8a35245 |
15 | 48d027a98 |
hex | 2bd58b8cd |
11766642893 has 2 divisors, whose sum is σ = 11766642894. Its totient is φ = 11766642892.
The previous prime is 11766642847. The next prime is 11766642911. The reversal of 11766642893 is 39824666711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7355292169 + 4411350724 = 85763^2 + 66418^2 .
It is an emirp because it is prime and its reverse (39824666711) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11766642893 - 210 = 11766641869 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11766642493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5883321446 + 5883321447.
It is an arithmetic number, because the mean of its divisors is an integer number (5883321447).
Almost surely, 211766642893 is an apocalyptic number.
It is an amenable number.
11766642893 is a deficient number, since it is larger than the sum of its proper divisors (1).
11766642893 is an equidigital number, since it uses as much as digits as its factorization.
11766642893 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2612736, while the sum is 53.
The spelling of 11766642893 in words is "eleven billion, seven hundred sixty-six million, six hundred forty-two thousand, eight hundred ninety-three".
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