Base | Representation |
---|---|
bin | 1010101101010101001100… |
… | …0110000101001011011101 |
3 | 1112200120111022000200021001 |
4 | 2223111103012011023131 |
5 | 3020400421230230331 |
6 | 41012504342510301 |
7 | 2323431130105423 |
oct | 253252306051335 |
9 | 45616438020231 |
10 | 11773899461341 |
11 | 382a3123346a6 |
12 | 13a1a3b135391 |
13 | 675373b582c4 |
14 | 2c9c07315113 |
15 | 1563ed388561 |
hex | ab5531852dd |
11773899461341 has 2 divisors, whose sum is σ = 11773899461342. Its totient is φ = 11773899461340.
The previous prime is 11773899461257. The next prime is 11773899461393. The reversal of 11773899461341 is 14316499837711.
11773899461341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11763898461316 + 10001000025 = 3429854^2 + 100005^2 .
It is a cyclic number.
It is not a de Polignac number, because 11773899461341 - 27 = 11773899461213 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11773899462341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5886949730670 + 5886949730671.
It is an arithmetic number, because the mean of its divisors is an integer number (5886949730671).
Almost surely, 211773899461341 is an apocalyptic number.
It is an amenable number.
11773899461341 is a deficient number, since it is larger than the sum of its proper divisors (1).
11773899461341 is an equidigital number, since it uses as much as digits as its factorization.
11773899461341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 27433728, while the sum is 64.
The spelling of 11773899461341 in words is "eleven trillion, seven hundred seventy-three billion, eight hundred ninety-nine million, four hundred sixty-one thousand, three hundred forty-one".
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