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11813345149 is a prime number
BaseRepresentation
bin10110000000010000…
…10101011101111101
31010111021220010000211
423000020111131331
5143143204021044
65232120552421
7565513530334
oct130010253575
933437803024
1011813345149
115012364071
122358322711
1311635a0878
14800d10d1b
154921a0634
hex2c021577d

11813345149 has 2 divisors, whose sum is σ = 11813345150. Its totient is φ = 11813345148.

The previous prime is 11813345147. The next prime is 11813345183. The reversal of 11813345149 is 94154331811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11348640900 + 464704249 = 106530^2 + 21557^2 .

It is an emirp because it is prime and its reverse (94154331811) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11813345149 - 21 = 11813345147 is a prime.

Together with 11813345147, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11813345147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906672574 + 5906672575.

It is an arithmetic number, because the mean of its divisors is an integer number (5906672575).

Almost surely, 211813345149 is an apocalyptic number.

It is an amenable number.

11813345149 is a deficient number, since it is larger than the sum of its proper divisors (1).

11813345149 is an equidigital number, since it uses as much as digits as its factorization.

11813345149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 51840, while the sum is 40.

The spelling of 11813345149 in words is "eleven billion, eight hundred thirteen million, three hundred forty-five thousand, one hundred forty-nine".