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11813604054011 is a prime number
BaseRepresentation
bin1010101111101001000110…
…1011000101001111111011
31112211100222101012222002022
42223322101223011033323
53022023230114212021
641043032250025055
72326335056425364
oct253722153051773
945740871188068
1011813604054011
113845137565851
1213a968011818b
1367903095a316
142cbad2586b6b
15157473e6c1ab
hexabe91ac53fb

11813604054011 has 2 divisors, whose sum is σ = 11813604054012. Its totient is φ = 11813604054010.

The previous prime is 11813604053917. The next prime is 11813604054013. The reversal of 11813604054011 is 11045040631811.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11813604054011 - 242 = 7415557542907 is a prime.

It is a super-2 number, since 2×118136040540112 (a number of 27 digits) contains 22 as substring.

Together with 11813604054013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11813604054013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906802027005 + 5906802027006.

It is an arithmetic number, because the mean of its divisors is an integer number (5906802027006).

Almost surely, 211813604054011 is an apocalyptic number.

11813604054011 is a deficient number, since it is larger than the sum of its proper divisors (1).

11813604054011 is an equidigital number, since it uses as much as digits as its factorization.

11813604054011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11520, while the sum is 35.

Adding to 11813604054011 its reverse (11045040631811), we get a palindrome (22858644685822).

The spelling of 11813604054011 in words is "eleven trillion, eight hundred thirteen billion, six hundred four million, fifty-four thousand, eleven".