11813604054013 has 2 divisors, whose sum is σ = 11813604054014. Its totient is φ = 11813604054012.

The previous prime is 11813604054011. The next prime is 11813604054053. The reversal of 11813604054013 is 31045040631811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9306660665124 + 2506943388889 = 3050682^2 + 1583333^2 .

It is a cyclic number.

It is not a de Polignac number, because 11813604054013 - 2¹ = 11813604054011 is a prime.

It is a super-2 number, since 2×11813604054013² (a number of 27 digits) contains 22 as substring.

Together with 11813604054011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11813604054011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5906802027006 + 5906802027007.

It is an arithmetic number, because the mean of its divisors is an integer number (5906802027007).

Almost surely, 2^{11813604054013} is an apocalyptic number.

It is an amenable number.

11813604054013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11813604054013 is an equidigital number, since it uses as much as digits as its factorization.

11813604054013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34560, while the sum is 37.

Adding to 11813604054013 its reverse (31045040631811), we get a palindrome (42858644685824).

The spelling of 11813604054013 in words is "eleven trillion, eight hundred thirteen billion, six hundred four million, fifty-four thousand, thirteen".