11814113 has 2 divisors, whose sum is σ = 11814114. Its totient is φ = 11814112.

The previous prime is 11814091. The next prime is 11814119. The reversal of 11814113 is 31141811.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7118224 + 4695889 = 2668^2 + 2167^2 .

It is an emirp because it is prime and its reverse (31141811) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11814113 is a prime.

It is not a weakly prime, because it can be changed into another prime (11814119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5907056 + 5907057.

It is an arithmetic number, because the mean of its divisors is an integer number (5907057).

Almost surely, 2^11814113 is an apocalyptic number.

It is an amenable number.

11814113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11814113 is an equidigital number, since it uses as much as digits as its factorization.

11814113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 96, while the sum is 20.

The square root of 11814113 is about 3437.1664201781. The cubic root of 11814113 is about 227.7545385946.

Adding to 11814113 its reverse (31141811), we get a palindrome (42955924).

The spelling of 11814113 in words is "eleven million, eight hundred fourteen thousand, one hundred thirteen".