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11837424294503 is a prime number
BaseRepresentation
bin1010110001000001110101…
…1110000101101001100111
31112220122110110012120002122
42230100131132011221213
53022421021104411003
641102012044300155
72331140260221563
oct254203536055147
945818413176078
1011837424294503
113854250460015
1213b220954165b
1367b358938092
142ccd11d8c6a3
15157dba2a1238
hexac41d785a67

11837424294503 has 2 divisors, whose sum is σ = 11837424294504. Its totient is φ = 11837424294502.

The previous prime is 11837424294389. The next prime is 11837424294511. The reversal of 11837424294503 is 30549242473811.

11837424294503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11837424294503 - 212 = 11837424290407 is a prime.

It is a super-2 number, since 2×118374242945032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11837424294583) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5918712147251 + 5918712147252.

It is an arithmetic number, because the mean of its divisors is an integer number (5918712147252).

Almost surely, 211837424294503 is an apocalyptic number.

11837424294503 is a deficient number, since it is larger than the sum of its proper divisors (1).

11837424294503 is an equidigital number, since it uses as much as digits as its factorization.

11837424294503 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5806080, while the sum is 53.

The spelling of 11837424294503 in words is "eleven trillion, eight hundred thirty-seven billion, four hundred twenty-four million, two hundred ninety-four thousand, five hundred three".