Base | Representation |
---|---|
bin | 10001001110100000001… |
… | …010000010110110000101 |
3 | 11012011121021011221211022 |
4 | 101032200022002312011 |
5 | 123343412031302203 |
6 | 2303455342320525 |
7 | 151345512265241 |
oct | 21164012026605 |
9 | 4164537157738 |
10 | 1183802994053 |
11 | 417058a23869 |
12 | 171519289145 |
13 | 8782aa85214 |
14 | 41421353421 |
15 | 20bd7c7ca38 |
hex | 113a0282d85 |
1183802994053 has 2 divisors, whose sum is σ = 1183802994054. Its totient is φ = 1183802994052.
The previous prime is 1183802994047. The next prime is 1183802994103. The reversal of 1183802994053 is 3504992083811.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1011808656769 + 171994337284 = 1005887^2 + 414722^2 .
It is a cyclic number.
It is not a de Polignac number, because 1183802994053 - 228 = 1183534558597 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1183802993986 and 1183802994004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1183802994553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 591901497026 + 591901497027.
It is an arithmetic number, because the mean of its divisors is an integer number (591901497027).
Almost surely, 21183802994053 is an apocalyptic number.
It is an amenable number.
1183802994053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1183802994053 is an equidigital number, since it uses as much as digits as its factorization.
1183802994053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1866240, while the sum is 53.
The spelling of 1183802994053 in words is "one trillion, one hundred eighty-three billion, eight hundred two million, nine hundred ninety-four thousand, fifty-three".
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