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118544117 is a prime number
BaseRepresentation
bin1110001000011…
…01011011110101
322021001122221212
413010031123311
5220321402432
615432451205
72636415446
oct704153365
9267048855
10118544117
1160a07a4a
1233849b05
131b737363
1411a5b2cd
15a6192b2
hex710d6f5

118544117 has 2 divisors, whose sum is σ = 118544118. Its totient is φ = 118544116.

The previous prime is 118544113. The next prime is 118544143. The reversal of 118544117 is 711445811.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117375556 + 1168561 = 10834^2 + 1081^2 .

It is an emirp because it is prime and its reverse (711445811) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 118544117 - 22 = 118544113 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (118544113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59272058 + 59272059.

It is an arithmetic number, because the mean of its divisors is an integer number (59272059).

Almost surely, 2118544117 is an apocalyptic number.

It is an amenable number.

118544117 is a deficient number, since it is larger than the sum of its proper divisors (1).

118544117 is an equidigital number, since it uses as much as digits as its factorization.

118544117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4480, while the sum is 32.

The square root of 118544117 is about 10887.7967008941. The cubic root of 118544117 is about 491.2395618775.

Adding to 118544117 its reverse (711445811), we get a palindrome (829989928).

The spelling of 118544117 in words is "one hundred eighteen million, five hundred forty-four thousand, one hundred seventeen".