11894130600013 has 2 divisors, whose sum is σ = 11894130600014. Its totient is φ = 11894130600012.

The previous prime is 11894130599921. The next prime is 11894130600031. The reversal of 11894130600013 is 31000603149811.

It is a happy number.

11894130600013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (11894130600031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11877521318884 + 16609281129 = 3446378^2 + 128877^2 .

It is an emirp because it is prime and its reverse (31000603149811) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11894130600013 - 2¹³ = 11894130591821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11894130600113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5947065300006 + 5947065300007.

It is an arithmetic number, because the mean of its divisors is an integer number (5947065300007).

Almost surely, 2^{11894130600013} is an apocalyptic number.

It is an amenable number.

11894130600013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11894130600013 is an equidigital number, since it uses as much as digits as its factorization.

11894130600013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 37.

Adding to 11894130600013 its reverse (31000603149811), we get a palindrome (42894733749824).

The spelling of 11894130600013 in words is "eleven trillion, eight hundred ninety-four billion, one hundred thirty million, six hundred thousand, thirteen".