Base | Representation |
---|---|
bin | 10001010100001110100… |
… | …000100010000011010111 |
3 | 11012202110121122012020222 |
4 | 101110032200202003113 |
5 | 123444004013200403 |
6 | 2310353304144555 |
7 | 151654024405523 |
oct | 21241640420327 |
9 | 4182417565228 |
10 | 1189949350103 |
11 | 419722428068 |
12 | 17275376815b |
13 | 8829a2753a7 |
14 | 4184577cd83 |
15 | 20e47675338 |
hex | 1150e8220d7 |
1189949350103 has 2 divisors, whose sum is σ = 1189949350104. Its totient is φ = 1189949350102.
The previous prime is 1189949350099. The next prime is 1189949350133. The reversal of 1189949350103 is 3010539499811.
It is a weak prime.
It is an emirp because it is prime and its reverse (3010539499811) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1189949350103 - 22 = 1189949350099 is a prime.
It is a super-2 number, since 2×11899493501032 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1189949350133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 594974675051 + 594974675052.
It is an arithmetic number, because the mean of its divisors is an integer number (594974675052).
Almost surely, 21189949350103 is an apocalyptic number.
1189949350103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1189949350103 is an equidigital number, since it uses as much as digits as its factorization.
1189949350103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1049760, while the sum is 53.
The spelling of 1189949350103 in words is "one trillion, one hundred eighty-nine billion, nine hundred forty-nine million, three hundred fifty thousand, one hundred three".
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