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11946390400471 is a prime number
BaseRepresentation
bin1010110111010111110001…
…0110110010110111010111
31120022001201111011021111011
42231311330112302313113
53031212201420303341
641224032422153051
72342045455643662
oct255657426626727
946261644137434
1011946390400471
113896487a3724a
12140b359b82787
13688702b8b567
142d42cbb206d9
1515ab4671eb81
hexadd7c5b2dd7

11946390400471 has 2 divisors, whose sum is σ = 11946390400472. Its totient is φ = 11946390400470.

The previous prime is 11946390400331. The next prime is 11946390400493. The reversal of 11946390400471 is 17400409364911.

It is a strong prime.

It is an emirp because it is prime and its reverse (17400409364911) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11946390400471 - 29 = 11946390399959 is a prime.

It is a super-3 number, since 3×119463904004713 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11946390400771) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5973195200235 + 5973195200236.

It is an arithmetic number, because the mean of its divisors is an integer number (5973195200236).

Almost surely, 211946390400471 is an apocalyptic number.

11946390400471 is a deficient number, since it is larger than the sum of its proper divisors (1).

11946390400471 is an equidigital number, since it uses as much as digits as its factorization.

11946390400471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 653184, while the sum is 49.

The spelling of 11946390400471 in words is "eleven trillion, nine hundred forty-six billion, three hundred ninety million, four hundred thousand, four hundred seventy-one".