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11946390400493 is a prime number
BaseRepresentation
bin1010110111010111110001…
…0110110010110111101101
31120022001201111011021111222
42231311330112302313231
53031212201420303433
641224032422153125
72342045455644023
oct255657426626755
946261644137458
1011946390400493
113896487a3726a
12140b359b827a5
13688702b8b583
142d42cbb20713
1515ab4671eb98
hexadd7c5b2ded

11946390400493 has 2 divisors, whose sum is σ = 11946390400494. Its totient is φ = 11946390400492.

The previous prime is 11946390400471. The next prime is 11946390400577. The reversal of 11946390400493 is 39400409364911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11367700046404 + 578690354089 = 3371602^2 + 760717^2 .

It is a cyclic number.

It is not a de Polignac number, because 11946390400493 - 28 = 11946390400237 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11946390400193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5973195200246 + 5973195200247.

It is an arithmetic number, because the mean of its divisors is an integer number (5973195200247).

Almost surely, 211946390400493 is an apocalyptic number.

It is an amenable number.

11946390400493 is a deficient number, since it is larger than the sum of its proper divisors (1).

11946390400493 is an equidigital number, since it uses as much as digits as its factorization.

11946390400493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2519424, while the sum is 53.

The spelling of 11946390400493 in words is "eleven trillion, nine hundred forty-six billion, three hundred ninety million, four hundred thousand, four hundred ninety-three".