Base | Representation |
---|---|
bin | 10110010000010101… |
… | …11010100001000101 |
3 | 1010211200201102111022 |
4 | 23020022322201011 |
5 | 143432222121132 |
6 | 5253340120525 |
7 | 602042232536 |
oct | 131012724105 |
9 | 33750642438 |
10 | 11948238917 |
11 | 508151881a |
12 | 2395536145 |
13 | 1185510974 |
14 | 814bc668d |
15 | 49de48e12 |
hex | 2c82ba845 |
11948238917 has 2 divisors, whose sum is σ = 11948238918. Its totient is φ = 11948238916.
The previous prime is 11948238859. The next prime is 11948238941. The reversal of 11948238917 is 71983284911.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11474480161 + 473758756 = 107119^2 + 21766^2 .
It is a cyclic number.
It is not a de Polignac number, because 11948238917 - 26 = 11948238853 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11948228917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5974119458 + 5974119459.
It is an arithmetic number, because the mean of its divisors is an integer number (5974119459).
Almost surely, 211948238917 is an apocalyptic number.
It is an amenable number.
11948238917 is a deficient number, since it is larger than the sum of its proper divisors (1).
11948238917 is an equidigital number, since it uses as much as digits as its factorization.
11948238917 is an evil number, because the sum of its binary digits is even.
The product of its digits is 870912, while the sum is 53.
Subtracting from 11948238917 its sum of digits (53), we obtain a square (11948238864 = 1093082).
The spelling of 11948238917 in words is "eleven billion, nine hundred forty-eight million, two hundred thirty-eight thousand, nine hundred seventeen".
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