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11952457757 is a prime number
BaseRepresentation
bin10110010000110110…
…00000100000011101
31010211222122202122122
423020123000200131
5143434312122012
65254010352325
7602123133422
oct131033004035
933758582578
1011952457757
11508393a469
122396a2b6a5
13118635a016
148155a3d49
1549e4cde72
hex2c86c081d

11952457757 has 2 divisors, whose sum is σ = 11952457758. Its totient is φ = 11952457756.

The previous prime is 11952457747. The next prime is 11952457787. The reversal of 11952457757 is 75775425911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11018910841 + 933546916 = 104971^2 + 30554^2 .

It is a cyclic number.

It is not a de Polignac number, because 11952457757 - 212 = 11952453661 is a prime.

It is a super-2 number, since 2×119524577572 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11952457699 and 11952457708.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11952457747) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5976228878 + 5976228879.

It is an arithmetic number, because the mean of its divisors is an integer number (5976228879).

Almost surely, 211952457757 is an apocalyptic number.

It is an amenable number.

11952457757 is a deficient number, since it is larger than the sum of its proper divisors (1).

11952457757 is an equidigital number, since it uses as much as digits as its factorization.

11952457757 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3087000, while the sum is 53.

The spelling of 11952457757 in words is "eleven billion, nine hundred fifty-two million, four hundred fifty-seven thousand, seven hundred fifty-seven".