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11956407299 is a prime number
BaseRepresentation
bin10110010001010100…
…00100110000000011
31010212021002102101222
423020222010300003
5143441320013144
65254231145255
7602201533214
oct131052046003
933767072358
1011956407299
115086097851
12239821522b
131187110925
14815d1140b
1549ea0e2ee
hex2c8a84c03

11956407299 has 2 divisors, whose sum is σ = 11956407300. Its totient is φ = 11956407298.

The previous prime is 11956407263. The next prime is 11956407301. The reversal of 11956407299 is 99270465911.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11956407299 is a prime.

Together with 11956407301, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11956407299.

It is not a weakly prime, because it can be changed into another prime (11956407899) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5978203649 + 5978203650.

It is an arithmetic number, because the mean of its divisors is an integer number (5978203650).

Almost surely, 211956407299 is an apocalyptic number.

11956407299 is a deficient number, since it is larger than the sum of its proper divisors (1).

11956407299 is an equidigital number, since it uses as much as digits as its factorization.

11956407299 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1224720, while the sum is 53.

The spelling of 11956407299 in words is "eleven billion, nine hundred fifty-six million, four hundred seven thousand, two hundred ninety-nine".