Base | Representation |
---|---|
bin | 110111101101101001… |
… | …0001111001110011011 |
3 | 102102211010121122001112 |
4 | 1233123102033032123 |
5 | 3430012113431001 |
6 | 130544023010535 |
7 | 11433603432452 |
oct | 1573322171633 |
9 | 372733548045 |
10 | 119643108251 |
11 | 46816463067 |
12 | 1b230299a4b |
13 | b38928a314 |
14 | 5b0dba3b99 |
15 | 31a39a9cbb |
hex | 1bdb48f39b |
119643108251 has 2 divisors, whose sum is σ = 119643108252. Its totient is φ = 119643108250.
The previous prime is 119643108197. The next prime is 119643108253. The reversal of 119643108251 is 152801346911.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-119643108251 is a prime.
Together with 119643108253, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 119643108199 and 119643108208.
It is not a weakly prime, because it can be changed into another prime (119643108253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 59821554125 + 59821554126.
It is an arithmetic number, because the mean of its divisors is an integer number (59821554126).
Almost surely, 2119643108251 is an apocalyptic number.
119643108251 is a deficient number, since it is larger than the sum of its proper divisors (1).
119643108251 is an equidigital number, since it uses as much as digits as its factorization.
119643108251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 119643108251 in words is "one hundred nineteen billion, six hundred forty-three million, one hundred eight thousand, two hundred fifty-one".
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