11980931327941 has 2 divisors, whose sum is σ = 11980931327942. Its totient is φ = 11980931327940.

The previous prime is 11980931327921. The next prime is 11980931328013. The reversal of 11980931327941 is 14972313908911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10397587271841 + 1583344056100 = 3224529^2 + 1258310^2 .

It is a cyclic number.

It is not a de Polignac number, because 11980931327941 - 2²¹ = 11980929230789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11980931327921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5990465663970 + 5990465663971.

It is an arithmetic number, because the mean of its divisors is an integer number (5990465663971).

Almost surely, 2^{11980931327941} is an apocalyptic number.

It is an amenable number.

11980931327941 is a deficient number, since it is larger than the sum of its proper divisors (1).

11980931327941 is an equidigital number, since it uses as much as digits as its factorization.

11980931327941 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2939328, while the sum is 58.

The spelling of 11980931327941 in words is "eleven trillion, nine hundred eighty billion, nine hundred thirty-one million, three hundred twenty-seven thousand, nine hundred forty-one".