11980931328013 has 2 divisors, whose sum is σ = 11980931328014. Its totient is φ = 11980931328012.

The previous prime is 11980931327941. The next prime is 11980931328071. The reversal of 11980931328013 is 31082313908911.

11980931328013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10583329759209 + 1397601568804 = 3253203^2 + 1182202^2 .

It is an emirp because it is prime and its reverse (31082313908911) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11980931328013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11980931328413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5990465664006 + 5990465664007.

It is an arithmetic number, because the mean of its divisors is an integer number (5990465664007).

Almost surely, 2^{11980931328013} is an apocalyptic number.

It is an amenable number.

11980931328013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11980931328013 is an equidigital number, since it uses as much as digits as its factorization.

11980931328013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 279936, while the sum is 49.

The spelling of 11980931328013 in words is "eleven trillion, nine hundred eighty billion, nine hundred thirty-one million, three hundred twenty-eight thousand, thirteen".